Statistic for Data Scientists 1| | Reading Notes© Peter Bruce

Statistic for Data Scientists 1| | Reading Notes

Estimates of Location

Mean; Weighter mean, Median, Weighted median, Trimmed mean, Robust, Outlier.

Mean $\overline{x} = \frac{\sum_ i^ n x_ i}{n}$
Trimmed mean $ \overline{x} = \frac{\sum_ {i=p+1} ^{n-p} x_ {(i)}}{n-2p}$
Weighted mean $\overline{x}_ w = \frac{\sum_ {i=1} ^ n w_ i x_ i}{\sum_ i ^ n w_ i }$

Estimates of Variability

Term Synonyms Description
Deviations errors, residuals The difference between the observed values and the estimate of location
Varuance mean-squared-error THe sum of squared deviations from the mean divided by $n - 1$ where n is the number of data values
Standard deviation l2-norm, Eucliden norm The square root of the variance.
Mean absolute deviation l1-norm, Manhattan norm The mean of the absolute value of the deviations from the mean.
Median absolute deviation from the median The median of the absolute value of the deviations from the median
Range The difference between the largest and the smallest value in a data set.
Order statistics Ranks Metrics based on the date values sorted from smallest to biggest.
Precentile quantile The value such that P percent of the values take on this value or less ad (100-P) percent take on this value or more.
Interquartile range IQR The differentce between the 75th percentile and the 25th percentile.

Deviation

Mean absolution deviation $\frac{\sum ^ n _ {i=1} | x_ i - \overline{x}|}{n}$
Variance $s^ 2 = \frac{\sum (x - \overline{x})^ 2}{n-1}$
Standard deviation $s = \sqrt{s^ 2}$

For Mean absolution deviation:

List <- c(1,2,3,4,5)
MAD <- function(List){
Tmp = 0
for( num in List){
Tmp = Tmp + abs(num - mean(List))
}
Result = Tmp/length(List)
return(Result)
}

'''
in R mad()

Instated of Tmp/length(List), in function mad(),
it using Tmp/(length(List)-1)
'''

For Variance:

List <- c(1,2,3,4,5)
VAR <- function(List){
Tmp = 0
for( num in List){
Tmp = Tmp + (num - mean(List))^2
}
Result = Tmp/(length(List)-1)
return(Result)
}
# var() in R

For Standard Deviation

List <- c(1,2,3,4,5)
SD <- function(List){
Tmp = 0
for( num in List){
Tmp = Tmp + (num - mean(List))^2
}
Result = Tmp/(length(List)-1)
Result = sqrt(Result)
return(Result)
}

# sd() in R

Why n - 1

In the intuitive denominator of n in the variance formulation, it would underestimate the true variance and the standard deviation. This is referred to as a biased estimate.
If you divided by $n-1$, the standard deviation becomes an unbiased estimate.

Test: function SD() and sd()
SD() is using $n$, which is biased estimate,
sd() is the base function of R, which use unbiased estimate.

SD <- function(List){
Tmp = 0
for( num in List){
Tmp = Tmp + (num - mean(List))^2
}
Result = Tmp/length(List)
Result = sqrt(Result)
return(Result)
}
Test <- function(List, i){
A = SD(List)
B = sd(List)
C = mad(List)
D = var(List)
Result = "|"
List_str = "$c(1,2,3,4,5,6,7,8,9,10)"
List_str_tmp = paste(List_str, "^ {",(1+ i/10),"}$",sep="")
Result = paste(Result, List_str_tmp, sep = "")
Result = paste(Result, "|",A,"|",B,"|", C,"|", D, "|",sep = "")
print(C)
#print(Result)
return(data.frame(A, B,C,D))
}
TB = data.frame()
for(i in c(0:10)){
List <- c(1,2,3,4,5,6,7,8,9,10)
List <- List ^(1+ i/10)
TB = rbind(TB, Test(List, i))
}
List SD sd mad var
$c(1,2,3,4,5,6,7,8,9,10)^ {1}$ 2.87228132326901 3.02765035409749 3.7065 9.16666666666667
$c(1,2,3,4,5,6,7,8,9,10)^ {1.1}$ 3.71464847156818 3.91558329233956 4.81903250216669 15.3317925192487
$c(1,2,3,4,5,6,7,8,9,10)^ {1.2}$ 4.77822834483576 5.03669491668582 6.21842448942231 25.3682956837688
$c(1,2,3,4,5,6,7,8,9,10)^ {1.3}$ 6.1203589266995 6.45142476870465 7.97443123015422 41.6208815462559
$c(1,2,3,4,5,6,7,8,9,10)^ {1.4}$ 7.81312940963156 8.23576152936081 10.1733320771185 67.8277679684995
$c(1,2,3,4,5,6,7,8,9,10)^ {1.5}$ 9.94716631430172 10.4852339392319 12.9217964296424 109.940130760421
$c(1,2,3,4,5,6,7,8,9,10)^ {1.6}$ 12.6363910464884 13.3199257038206 16.2215684620237 177.420420755302
$c(1,2,3,4,5,6,7,8,9,10)^ {1.7}$ 16.0239981545644 16.8907771302528 19.8184284109695 285.298352063871
$c(1,2,3,4,5,6,7,8,9,10)^ {1.8}$ 20.289967545938 21.3875036986871 24.1444312624589 457.425314461353
$c(1,2,3,4,5,6,7,8,9,10)^ {1.9}$ 25.6605043589986 27.0485465610381 29.3423269903854 731.623871064649
$c(1,2,3,4,5,6,7,8,9,10)^ {2}$ 32.4199012953463 34.1735765370459 35.5824 1167.83333333333

(Click the tag “var” below to dismiss the line “var”)

Percentile

Percentile was widely used in boxplot (interquartile range or IQR). It was more sensitive to the outliers, and the massive calculation also restricted its applicability since it needs sorting the data set though there are a machine learning algorithms to get an approximate percentile very quickly[1].

When the data (n is even):
$$
100 \frac{j}{n} \le P < 100\frac{j+1}{n}
$$

Formally, the percentile is the weighted average:

$$
P = (1 - w) x _ {(j)} + wx_ {j + 1}
$$

IQR in R:

$$
IQR(x) = quantile(x, 3/4) - quantile(x, 1/4)
$$

R
IQR(c(1,2,3,4,5,6,7,8,9,10))
[1] 4.5

Variation illustration

R
library(ggplot2)
library(patchwork)

P1 <- ggplot(chickwts, aes(feed, weight, fill = feed, group = feed)) +
geom_point() + geom_boxplot( alpha = 0.4) + theme_bw()+
labs( title= "Boxplot")
P2 <- ggplot(chickwts, aes(weight, fill = feed, group = feed)) +
geom_density(alpha = 0.4) + theme_bw() +
labs( title= "Density Plot")
P3 <- ggplot(chickwts, aes(weight, fill = feed, group = feed)) +
geom_histogram( alpha = 0.4)+ theme_bw()+
labs( title= "Histogram Plot")

(P1|P3) /P2
Variation Illustration
@ Karobben

  1. Qi Zhang and Wei Wang. 2007. A Fast Algorithm for Approximate Quantiles in High Speed Data Streams. In Proceedings of the 19th International Conference on Scientific and Statistical Database Management (SSDBM '07). IEEE Computer Society, USA, 29. DOI:https://doi.org/10.1109/SSDBM.2007.27 ↩︎

Statistic for Data Scientists 1| | Reading Notes

https://karobben.github.io/2021/04/13/LearnNotes/statistics-ds-1/

Author

Karobben

Posted on

2021-04-13

Updated on

2024-01-11

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